4x-[3x-(8+x)]=2x+8

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Solution for 4x-[3x-(8+x)]=2x+8 equation:


Simplifying
4x + -1[3x + -1(8 + x)] = 2x + 8
4x + -1[3x + (8 * -1 + x * -1)] = 2x + 8
4x + -1[3x + (-8 + -1x)] = 2x + 8

Reorder the terms:
4x + -1[-8 + 3x + -1x] = 2x + 8

Combine like terms: 3x + -1x = 2x
4x + -1[-8 + 2x] = 2x + 8
4x + [-8 * -1 + 2x * -1] = 2x + 8
4x + [8 + -2x] = 2x + 8

Reorder the terms:
8 + 4x + -2x = 2x + 8

Combine like terms: 4x + -2x = 2x
8 + 2x = 2x + 8

Reorder the terms:
8 + 2x = 8 + 2x

Add '-8' to each side of the equation.
8 + -8 + 2x = 8 + -8 + 2x

Combine like terms: 8 + -8 = 0
0 + 2x = 8 + -8 + 2x
2x = 8 + -8 + 2x

Combine like terms: 8 + -8 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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